Basic Concepts of Chemistry Important Points
Important formulae :
- No of moles=massMolar mass
- No of moles of gas=Volume at STP22.4
- No of moles of Particles=No of Particles6.023×1023
- No of moles of solute=Molarity×Vol(L)
- Eq. wt. of a salt=M.W. of saltTotal +ve charge of metal ion
- Eq. wt. of element=Atomic WeightValency
- Avg. atomic mass=m×a+n×bm+n where, a + b are atomic masses and m + n are precentage.
- % of element in compound=n(at mass of element)MW of compound×100 where, n= No. of atoms of that element
- Molarity=w×1000M.W.×V(ml)
- Normality=w×1000E.W.×V(ml)
- Molality=w×1000M.W.×W(g) W = Weight of solvent
- Mole fraction(X)=nn+N
- %W/W=W×100W+W0
- ppm=weight(vol) of solute×106weight(vol) of solution
- Molecalar weight=2×V.D.
- Eq. wt. of metal=Wt. of metalwt. of H2 displaced×1.008
- Eq. wt. of metal=Wt. of metal×11200Vol of H2 displaced at STP(mL)
- Eq. wt. of metal=Wt. of metal×35.5Wt. of Chlorine combined
- Eq. wt. of metal=Wt. of metal×11200Vol of Cl2 combined at STP(mL)
- Eq. wt. of metal=Wt. of metal×8Wt. of oxygen combined
- Eq. wt. of metal=Wt. of metal×5600Vol of O2 displaced at STP(mL)
- Molority=%W/W×density×10Molecular weight
- M1V1=M2V2 (Molarity equation)
- N1V1=N2V2 (Normality equation)
- n=Molecular weightEmpirical formula Weight
- ∘F=92(∘C)+32
- K=∘C+273.15
- 1L=1dm3, 1mL=1cm3
Important Facts :
- Antoine Lavoisier - Law of conservation of mass
- Joseph proust - Law of definite proportions
- John Dalton - Law of Multiple proportions
- Richter - Law of combining weights.
- Gay Lussac - Law of combining Volumes.
- 1 amu=1.6605×10−23 gram
- Mass of C atom=1.9926×10−23 gram
- Avogadro′s number(NA)=6.022×1023
- AZT = Azido thymidine,drug used for aids victims.
- The limiting reagent is the reagent that is entirely consumed when a reaction goes to completion. Its amount limits the amount of the product formed.
Precision and Accuracy.
The term precision refers for the closeness of the set of values obtained form identical measurements of a quantity.
Accuracy refers to the closeness of a single measurement to its true value.
Let us take an example to illustrute. this. Three students were asked to determine the mass of a piece of metal where mass is known to be 0.520g. Data obtained by each Student are recorded in table below
Student | Mesurements in g. | |||
1 | 2 | 3 | Average | |
A | 0.521 | 0.515 | 0.509 | 0.515 |
B | 0.516 | 0.515 | 0.514 | 0.515 |
C | 0.521 | 0.500 | 0.520 | 0.520 |
The data for student A are neither, precise nor accurate. The data for student B are precise but not accurate. The data for student C are both precise and accurate.