61.  Which of the following chemical equation is incorrectly balanced ?

A. \(Sb_{2}S_{3}+12HCl\rightarrow 2H_{3}SbCl_{6}+3H_{2}S\)

B. \(3IBr+4NH_{3}\rightarrow NI_{3}+3NH_{4}Br\)

C. \(2KrF_{2}+2H_{2}O\rightarrow 2Kr+2O_{2}+4HF\)

D. \(PCl_{3}+3H_{2}O\rightarrow H_{3}PO_{3}+3HCl\)

Answer : Option C

View Answer

62.  

Match the following

Column -I             Column -II

(i) \(Cl_{2}O_{3}\)            (P) basic anhydride

(ii) \(Li_{2}O\)               (Q) acid anhydride

(iii) \(CO_{2}\)              (R) base

A. (i) - (q) (ii) - (p) (iii) - (q)

B. (i) - (r) (ii) - (q) (iii) - (p)

C. (i) - (p) (ii) - (q) (iii) - (r)

D. (i) - (p) (ii) - (q) (iii) - (p)

Answer : Option A

View Answer

63.  How many g of NaOH can be obtained by reaction of 1 Kg of \(Na_{2}CO_{3}\) with \(Ca(OH)_{2}\) ?

A. 106 g

B. 850 g

C. 755 g

D. 943 g

Answer : Option C

View Answer

64.  How much calcium oxide (CaO) can be obtained by heating 200 Kg of lime stone that is 95% pure \(CaCO_{3}\) ?

A. 56 Kg

B. 190 Kg

C. 170 Kg

D. 107 Kg

Answer : Option D

View Answer

65.  Calculate the amount of NaOH required to neutralize 100 mL 0.1M \(H_{2}SO_{4}\)

A. 40 g

B. 0.4 g

C. 80 g

D. 0.8 g

Answer : Option D

Explanation :

→ 0.1M \(H_{2}SO_{4}\) = 1000 mL solution contains 0.1 mol \(H_{2}SO_{4}\)

\(\therefore \) 100 mL solution contains 0.01 mol \(H_{2}SO_{4}\)

→ \(\therefore \) mass of \(H_{2}SO_{4}\) = 0.01 x 98 = 0.98 g

\(2NaOH+H_{2}SO_{4}\rightarrow Na_{2}SO_{4}+2H_{2}O\)

   2(40)g       98g

    (?)           \(\therefore \) 0.98g

                  = \(\frac{80\times 0.98}{98}\)

                  = 0.8 g

View Answer

66.  3g of an oxide of a metal is converted into chloride and it yielded 5 g of chloride. Find the equivalent weight of the metal.

A. 33.25

B. 3.325

C. 12

D. 20

Answer : Option A

Explanation :

→ \(\frac{Wt\ of\ metal\ oxide}{Wt\ of\ metal\ Choride}\) = \(\frac{Eq\ wt\ of\ metal+Eq\ wt\ of\ oxide}{Eq\ wt\ of\ metal+Eq\ wt\ of\ Choride}\)

\(\therefore \frac{3}{5}=\frac{E+8}{E+35.5}\)

\(\therefore E=33.25\)

View Answer

67.  A compound contains two oxygen atoms, four carbon atoms and number of hydrogen atoms is double of carbon atoms. What is the density of vapour of this compound ?

A. 88

B. 44

C. 132

D. 72

Answer : Option B

Explanation :

→ M.F. \(C_{4}H_{8}O_{2}\)

\(\therefore \) Molar mass = 88

\(\therefore \) Vapour density = \(\frac{88}{2}\) =44

View Answer

68.  The number of molecules in 100 mL of each of \(O_{2}\), \(NH_{3}\) and \(CO_{2}\) at STP are

A. \(CO_{2} < O_{2} < NH_{3}\)

B. \(NH_{3} < O_{2} < CO_{2}\)

C. \(NH_{3} = CO_{2} < O_{2}\)

D. \(NH_{3} = CO_{2} = O_{2}\)

Answer : Option D

Explanation :

→ Equal volumes under identical conditions contain equal no. of molecules

View Answer

69.  Which of the following represents the formula of a compound which contains 26% nitrogen and 74% oxygen ?

A. \(N_{2}O\)

B. \(NO\)

C. \(NO_{2}\)

D. \(N_{2}O_{5}\)

Answer : Option D

Explanation :

\(N_{\frac{26}{14}}O_{\frac{74}{16}}\) = \(N_{1.85}O_{4.625}\) = \(N_{2}O_{5}\)

View Answer

70.  \(NKg^{-1}\) is the unit of

A. Momentum

B. Velocity

C. Pressure

D. Acceleration

Answer : Option D

Explanation :

→ \(F=ma\)

\(a=\frac{f}{m}=\frac{N}{Kg}=NKg^{-1}\)

View Answer