81.  For a reaction \(A+2B\rightarrow C\), the amount of C formed by starting the reaction with 5 moles of A and 8 moles of B is

A. 5 moles

B. 8 moles

C. 16 moles

D. 4 moles

Answer : Option D

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82.  100 mL of \(PH_{3}\) on heating forms P and \(H_{2}\). The volume change in the reaction is

A. an increase of 50 mL

B. an increase of 100 mL

C. an increase of 150 mL

D. a decrease of 50 mL

Answer : Option A

Explanation :

\(2PH_{3(g)}\rightarrow 2P_{(s)}+3H_{2(g)}\)

2 mL                               3mL

\(\therefore \) 100 mL                        (?)

                                      \(=\frac{100\times 3}{2}=150\ mL\)

\(\therefore \) Increase = 50 mL

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83.  An organic compound made of C, H, and N contains 20% nitrogen. Its molecular weight is (WB JEE 2009)

A. 70

B. 140

C. 100

D. 65

Answer : Option A

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84.  Volume occupied by one molecule of water \(\left ( d=1\ gm\ cm^{-3} \right )\) is

A. \(9\times 10^{-23}\ cm^{3}\)

B. \(6.02\times 10^{-23}\ cm^{3}\)

C. \(3\times 10^{-23}\ cm^{3}\)

D. \(5.5\times 10^{-23}\ cm^{3}\)

Answer : Option C

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85.  Calculate the number of moles in \(1\ m^{3}\) gas at STP.

A. 4.46

B. 44.6

C. 446

D. 4460

Answer : Option B

Explanation :

\(1\ m^{3}\) = 1000L

At STP, 22.4 L = 1 mol

\(\therefore \) 1000 L = \(\frac{1000}{22.4}\) = 44.6

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86.  An ore contains 1.24% of the mineral argentite \(Ag_{2}S\) by mass. How many grams of this ore would have to be processed in order to obtain 1.0 g of pure solid silver ?

A. 23.15 g

B. 69.45 g

C. 92.6 g

D. 46.3 g

Answer : Option C

Explanation :

\(Ag_{2}S\)      \(Ag\) 

248 g          216 g

 (?)            \(\therefore \) 1.0 g

= 1.148 g

 

\(ore\)          \(Ag_{2}S\) 

100 g          1.24 g

 (?)            \(\therefore \) 1.148 g

= 92.58 ≈ 92.6 g

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87.  Find the electric charge in coulomb of 9.0 gm of \(Al^{3+}\) ions.

A. \(9.6\times 10^{4}\)

B. \(6.9\times 10^{4}\)

C. \(2.9\times 10^{5}\)

D. \(4.8\times 10^{-19}\)

Answer : Option A

Explanation :

No of moles of \(Al^{3+}\) = \(\frac{9}{27}\) = 0.33

\(\therefore \) No of \(Al^{3+}\) ions = \(0.33\times 6.022\times 10^{23}\) = \(2\times 10^{23}\)

\(\therefore \) Electric charge = \(3\times 1.602\times 10^{-19}\times 2\times 10^{23}\) = \(9.6\times 10^{4}\) Coulomb

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88.  Which of the following is not a homogeneous mixture ?

A. Smoke

B. Air

C. Brass

D. Aqueous solution of sugar

Answer : Option A

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89.  Which of the following has the largest number of atoms ?

A. 0.5 g atom of Cu

B. 0.635 g of Cu

C. 0.25 moles of Cu atom

D. 1 g of Cu

Answer : Option A

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90.   27 g of Al (at mass = 27) will react with oxygen equal to (IIT 1978)

A. 24 g

B. 8 g

C. 40 g

D. 10 g

Answer : Option A

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